Martingale Problem and Boltzmann equation: Difference between pages

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(Classical Martingale Problem)  Given a (local) linear operator $\mathcal{L}: C^2(\mathbb{R}^n) \to C(\mathbb{R}^n)$ Martingale Problem for $\mathcal{L}$ consists in finding for each $x_0 \in \mathbb{R}^d$ a probability measure $\mathbb{P}^{x_0}$ over the space of all continuous functions $X: [0,+\infty) \to \mathbb{R}^d$ such that
The Boltzmann equation is an evolution equation used to describe the configuration of particles in a gas, but only statistically. Specifically, if the probability that a particle in the gas lies in some region $A$ of phase space $\mathbb{R}^d\times \mathbb{R}^d$ at time $t$ is given by


\begin{equation*}
\begin{equation*}
\mathbb{P}^{x_0}\left ( X(0)=x_0 \right ) = 1
\int_A f(x,v,t)dxdy
\end{equation*}
\end{equation*}


and whenever $f \in C^2(\mathbb{R}^d)$ we have that
then $f(x,v,t)$ solves the non-local equation


\begin{equation*}
\begin{equation*}
f(X(t))-f(X(0))-\int_0^t \mathcal{L} f(X(s)) \;ds
\partial_t f + v \cdot \nabla_x f = Q(f,f)
\end{equation*}
\end{equation*}


is a [[Martingale| Local Martingale]] under $\mathbb{P}^{x_0}$. If for any $x \in \mathbb{R}^d$ there exists a unique $\mathbb{P}^x$ satisfying the above conditions we say that the Martingale Problem for $\mathcal{L}$ is well posed.
where $Q(f,f)$ is the Boltzmann collision operator, given by
 
Note that existence for the Martingale Problem implies existence of solutions to the Cauchy problem for the operator $\mathcal{L}$ with initial data in $C^2(\mathbb{R}^d)$, indeed, if $f \in C^2(\mathbb{R}^d)$ then we can define
 
\begin{equation*}
u(x,t) = \mathbb{E}_{\mathbb{P}^x} [ f(X_t) ]
\end{equation*}
 
Then it can be shown that $u(x,t)$ is a classical solution to the problem


\begin{equation*}
\begin{equation*}
\left \{ \begin{array}{ll}
Q(f,f)(v) = \int_{\mathbb{R}^d}\int_{\mathbb{S}^{d-1}} B(v-v_*,e) (f(v')f(v'_*)-f(v)f(v_*) d\sigma(e) dv_*
u_t  = \mathcal{L}u & \text{ in } \mathbb{R}^d\times \mathbb{R}_+\\
u\;\;  = f & \text{ for } t=0
\end{array}\right.
\end{equation*}
\end{equation*}


Thus at first glance it would seem that  well-posedness for the Martingale Problem for $\mathcal{L}$ is a stronger fact than that the well-posedness for the corresponding Cauchy problem, but often one can turn this around and show the well-posedness for the Martingale Problem after understanding the Cauchy problem for $\mathcal{L}$ well enough.
where $d\sigma$ denotes the Hausdorff measure on $\mathbb{S}^{d-1}$, and given $v,v_* \in \mathbb{R}^d$ and $e \in \mathbb{S}^{d-1}$ we write
 
The oldest example of a Martingale Problem is when $\mathcal{L}= \Delta$, the classical Laplacian, in this case the unique solution $\mathbb{P}^{x}$ corresponds to the standard Brownian motion or Wiener process. Using this as a base case and using basic Ito Calculus one can solve the corresponding problem for a generic second order operator


\begin{equation*}
\begin{align*}
\mathcal{L} u = \text{Tr}(A(x)D^2u(x))+b(x)\cdot \nabla u(x)+c(x)u(x)
v'  & = v-(v-v_*,e)e\\
\end{equation*}
v'_* & = v_*+(v-v_*,e)e
\end{align*}


where $A(x)\geq 0$, $c(x)\leq 0$ and $A,b,c$ are all Lipschitz functions of $x$. The case where the coefficients are merely continuous is much harder and it is an important result of Stroock and Varadhan that says still in this case the Martingale Problem is well posed.
where $B$, known as the Boltzmann collision kernel, measures the strength of collisions in different directions.

Revision as of 10:42, 20 November 2012

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The Boltzmann equation is an evolution equation used to describe the configuration of particles in a gas, but only statistically. Specifically, if the probability that a particle in the gas lies in some region $A$ of phase space $\mathbb{R}^d\times \mathbb{R}^d$ at time $t$ is given by

\begin{equation*} \int_A f(x,v,t)dxdy \end{equation*}

then $f(x,v,t)$ solves the non-local equation

\begin{equation*} \partial_t f + v \cdot \nabla_x f = Q(f,f) \end{equation*}

where $Q(f,f)$ is the Boltzmann collision operator, given by

\begin{equation*} Q(f,f)(v) = \int_{\mathbb{R}^d}\int_{\mathbb{S}^{d-1}} B(v-v_*,e) (f(v')f(v'_*)-f(v)f(v_*) d\sigma(e) dv_* \end{equation*}

where $d\sigma$ denotes the Hausdorff measure on $\mathbb{S}^{d-1}$, and given $v,v_* \in \mathbb{R}^d$ and $e \in \mathbb{S}^{d-1}$ we write

\begin{align*} v' & = v-(v-v_*,e)e\\ v'_* & = v_*+(v-v_*,e)e \end{align*}

where $B$, known as the Boltzmann collision kernel, measures the strength of collisions in different directions.