[Maxima] Simplify x^p^(1/p) to r?
garyo-maxima at genarts.com
Fri May 18 10:32:46 CDT 2007
Raymond Toy <raymond.toy <at> ericsson.com> writes:
> Gary O wrote:
> > Q: why doesn't this return x?
> > ratsimp(x^p^(1/p))
> > If maxima doesn't know that x^y^z => x^(y*z), can I teach it somehow?
> But what is 2^3^4? I think ^ is right associative, so 2^3^4 is not
> 2^12, but 2^81.
Good idea, but even if I use parens it doesn't get it:
returns (x^p)^(1/p), not just x.
But -- oh ho, adding assumptions makes it work!
Cool. Not sure why it thinks this identity only holds for nonnegative x (i.e
real result), but anyway I know what to do to help it get it right now.
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