dastew at sympatico.ca
Sun Feb 15 10:39:24 CST 2009
Robert Dodier wrote:
> On 2/14/09, Doug Stewart <dastew at sympatico.ca> wrote:
>> Thank You !!!!
> I'm glad to hear it;s useful to you.
>> here is one example that needs a little polish :-)
>> with the "-" in the exponential it doesn't work
>> (%i77) apply_z_transform (z_transform (a+b*(e^(-p*T))^(m) , m, z));
> Did you mean to write %e^x or exp(x) instead of e^x ?
> I think with the existing rules, it can be solved with %e^x or exp(x).
Yes it does work with exp( -a m)
I have been trying to add a rule that would work with b^(-a*m) but no
I think (b^-a)^m gets changed to (1/ b^(a))^m before it gets to
Any way I am just trying to learn more. what you provided worked for the
question that I had.
> That said, it should work for anyway; I 'll try to add some rules
> for that.
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