robert.dodier at gmail.com
Thu Jun 25 10:27:01 CDT 2009
On 6/25/09, Leo Butler <l.butler at ed.ac.uk> wrote:
> I believe that lbfgs attempts to compute the gradient symbolically, and
> there is no means to supply this gradient if it is unable to compute it.
> Is this correct?
You can specify the figure of merit and gradient together as a list.
lbfgs ([x^2 + y^2, [2*x, 2*y]], [x, y], ....);
I guess it isn't documented. Sorry about that.
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