[Maxima] substituting function in diff
david.webb at noc.soton.ac.uk
Wed Jul 15 09:06:54 CDT 2009
On Tuesday 14 July 2009 18:24:59 Stavros Macrakis wrote:
> I'm not sure I understand your whole problem, but have you taken a look at
> You can do things like
> substinpart( myfavoritefunction( piece ) , expr, 2, 2, 1 )
> which extracts inpart(expr,2,2,1), calls your function on it, and returns an
expression with the value in place of the original subexpression.
Many thanks - this is just what I wanted. I thought I had read all the
relevant bits of the manual but ... . I had also tried '?? replace' but
not '?? inpart'!
More information about the Maxima