$f(x, y, z) = a x^2 + b y^2 + c z^2 + 2h x + 2k y + 2m z +2p xy + 2q yz + 2zx + d = 0.$
If
we are very lucky, then the intersection of the graph of $f(x, y, z) = 0$
with every plane $x
= X$ is exactly the same. In other words, $f(X, y, z) = 0$
for all $X$.
This can happen only if $f(x,
y, z)$ does not depend on $X$.
When $f(x,
y, z)$
is independent of one of the variables $x, y$ or $z$, we'll say the
graph of $f = 0$ is a CYLINDRICAL
SURFACE.
Both
surfaces to the right are good examples. Can you see that the first one
is the graph of $x^2+y^2
= r^2$ for some $r$,
while the second one is the graph of $z-y^2 = 0$? |
![]() |
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We're also pretty familiar with the case when EVERY plane cuts the surface in a circle except that now the circle may change with the plane. This is more familiar to us if we think of it simply as a surface, not something to slice!
| A
SPHERE of
radius $r$ centered at the origin
consists of all points $(x,
y, z)$ a distance $r$ from $(0, 0, 0)$.
By
the distance formula this means that $x^2 + y^2 + z^2 = r^2.$
If we shift the center to $(h, k, m)$ the equation
becomes$(x-h)^2 + (y-k)^2 + (z-m)^2 = r^2\,,$
which after expansion is$x^2 + y^2 + z^2 - 2h x - 2k y -2m z + d = 0$
for some constant $d$. Cutting
this sphere with the horizontal plane $z
= 1$ gives a circle; algebraically, this means setting $z = 1$ which
then gives the circle$x^2 + y^2 = r^2 - 1.$
What does this mean if $r = 1$ or $r < 1$?
In fact,
every plane cuts a sphere either in a circle or a point, or misses the
sphere altogether. The graphic to the right shows the circle case. |
![]() |
![]() CONE: $z^2 = x^2 + y^2$
|
![]() PARABOLOID: $z = x^2 + y^2$
|

Is it becoming clearer how the other surfaces go? Here they are along with the corresponding quadratic relations. Try constructing both vertical and horizontal slices.
ONE-SHEETED HYPERBOLOID: ![]() $x^2 + y^2 - z^2 = 1$ |
ELLIPSE: ![]() $\displaystyle{\frac{x^2}{a^2} + \frac{y^2}{b^2} +\frac{z^2}{c^2} = 1}$ What's the significance of $a, b,$ $c$? |
TWO-SHEETED HYPERBOLOID:![]() $z^2 - x^2 - y^2 = 1$ |