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Problem 1. Solve the equation tex2html_wrap_inline34 via Newton's method, taking as your initial guess tex2html_wrap_inline36 . Express your answer to at least 5 decimal places. [If done correctly, this should only take 4 or 5 iterations. If your results do not stabilize that fast, you made a mistake somewhere!]

Let tex2html_wrap_inline38 , tex2html_wrap_inline40 .

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So the answer to 5 decimal places is x= 2.35335.

Problem 2. Consider the differential equation dy/dx = x/y, with the initial condition y(0)=1.

a) Use Euler's method with tex2html_wrap_inline58 to approximate y(2).

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b) Solve the differential equation to find y(2) exactly.

y dy = x dx, so tex2html_wrap_inline74 . Plugging in y(0)=1 gives C=1/2, so tex2html_wrap_inline80 . tex2html_wrap_inline82 .

Problem 3. Suppose the New York Yankees and the San Diego Padres play a 7 game series. Each game is independent, with the Yankees having a 60% chance of winning. What is the probability that the Yankees will win 4 or more of the 7 games? Your written answer should be correct to at least 3 decimal places (e.g. 0.387, or 38.7%)

This is binomial. n=7, p=0.6, q=1-p=0.4.

tex2html_wrap_inline90 .

Problem 4. The rare Tasmanian Guppy (an imaginary fish whose name I just made up) can live for up to a year. Its actual lifespan X (in years) is given by a continuous random variable with pdf

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a) Find the corresponding cdf (i.e. F(x)) for all values of x.

displaymath100

b) What is the probability of a randomly selected guppy living between 3 and 6 months?

F(1/2)-F(1/4) = 0.2539.

c) What is the average lifespan of a Tasmanian Guppy.

tex2html_wrap_inline104 .

Problem 5. A computer generates seventy-five independent random numbers, each uniformly distributed between 0 and 2.

a) What is the probability that the first random number is between 0.9 and 1.5?

This is uniform with a=0 and b=2. P(0.9 < X < 1.5)=(1.5-0.9)/(2-0)=0.3.

b) Let S be the sum of the random numbers. What is the mean value of S? What is the standard deviation?

For each number, the mean is (a+b)/2=1 and the standard deviation is tex2html_wrap_inline118 . For the sum of n=75 numbers, the mean is 75 times bigger and the standard deviation tex2html_wrap_inline122 times bigger, so tex2html_wrap_inline124 and tex2html_wrap_inline126 .

c) What is the probability that S is between 70 and 85?

The sum of lots of random variables is normal, in this case with tex2html_wrap_inline124 and tex2html_wrap_inline132 . Let Z=(S-75)/5. Then P(70<S<85)=P(-1 < Z< 2)=0.3413+0.4772 = 0.8185.




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Lorenzo Sadun
Thu Nov 19 12:32:33 CST 1998