M340L First Midterm Exam Solutions.  February 12, 2003


1. Find all solutions to the system of equations:

eqnarray8

Is the set of solutions empty, a point, a line, a plane, or some other geometric shape? If it is a line or a plane, express this set in parametric form.

The augmented matrix reduces to tex2html_wrap_inline55 . There is one free variable, so the solutions form a line, which can be parametrized as
tex2html_wrap_inline57 .

2. Consider the matrix and vector

displaymath59

a) Is tex2html_wrap_inline61 in the span of the columns of A? If so, write tex2html_wrap_inline61 explicitly as a linear combinations of the columns.

The augmented matrix [A | b] reduces to tex2html_wrap_inline69 . Thus there are no solutions to tex2html_wrap_inline71 , so tex2html_wrap_inline61 is NOT a linear combination of the columns of A.

b) Are the columns of A linearly independent? If not, write the zero vector as a nontrivial linear combination of the columns of A.

A by itself row-reduces to tex2html_wrap_inline83 , so Ax=0 boils down to tex2html_wrap_inline87 , tex2html_wrap_inline89 , tex2html_wrap_inline91 free. Setting tex2html_wrap_inline93 gives the solution tex2html_wrap_inline95 . That is, tex2html_wrap_inline97 .

3. Consider the linear transformation tex2html_wrap_inline99 given by

displaymath101

a) Find the matrix of T.

tex2html_wrap_inline105

b) Is T one-to-one? Why or why not?

Row reducing A gives two pivots. Since there are 3 columns, there is a free variable, so T is NOT one-to-one.

c) Is T onto? Why or why not?

There is a pivot in each row, so T is onto.

4. Indicate whether each of these matrices is invertible. If it is, find the inverse. If it isn't invertible, explain why.

a) tex2html_wrap_inline117

The determinant is tex2html_wrap_inline119 , so the matrix is NOT invertible.

b) tex2html_wrap_inline121

By row-reducing tex2html_wrap_inline123 you get tex2html_wrap_inline125 , where tex2html_wrap_inline127

5. Indicate whether each of these statements is true or false. If a statement is sometimes true and sometimes false, write ``false''. You do NOT have to justify your answers. There is no penalty for wrong answers, so go ahead and guess if you are unsure of your answer.

a) The columns of a tex2html_wrap_inline129 matrix must be linearly dependent.

True. There are at most 4 pivots, which cannot fill out 5 columns

b) The columns of a tex2html_wrap_inline129 matrix must span tex2html_wrap_inline133 .

False. There may be fewer than 4 pivots.

c) If two matrices A and B have different sizes, then the sum A + B is not defined.

True.

d) If two matrices A and B have different sizes, then the product AB is not defined.

False. A and B don't have to be the same size. Rather, the WIDTH of A must match the HEIGHT of B.

e) If A and B are inverses, then AB=BA.

True. AB=BA=I

f) If a set tex2html_wrap_inline163 of 2 or more vectors is linearly dependent, then one of the vectors is a linear combination of the others.

True. We proved this in class.

g) If the columns of a tex2html_wrap_inline165 matrix are linearly independent, then they span tex2html_wrap_inline133 .

True. If the columns are linearly independent, then there are 4 pivots, so there is a pivot in each row, so the columns span tex2html_wrap_inline133 .

h) If the columns of an tex2html_wrap_inline171 matrix are linearly independent, then they span tex2html_wrap_inline173 .

False. If tex2html_wrap_inline175 , then having pivots in each column does NOT equate to having pivots in each row.

i) If a tex2html_wrap_inline177 matrix A has exactly 3 pivots, then the linear transformation tex2html_wrap_inline181 is one-to-one.

True. There are pivots in each column, hence there are no free variables.

j) If a tex2html_wrap_inline177 matrix A has exactly 3 pivots, then the linear transformation tex2html_wrap_inline181 is onto.

False. One row doesn't have a pivot.



Lorenzo Sadun
Wed Feb 12 08:39:45 CST 2003