[Maxima] integrate(x/(1-x^2),x)?

Stavros Macrakis macrakis at alum.mit.edu
Mon Feb 13 13:37:29 CST 2006

> Maxima currently says
> integrate(x/(1-x^2),x) ->
> -log(1-x^2)/2
> integrate(x/(x^2-1),x) ->
> log(x^2-1)/2

I must be missing something obvious here.  These both seem like correct answers.

Are you expecting them to both be giving results real for abs(x)<1 or
for abs(x)>1?

More information about the Maxima mailing list