[Maxima] integrate(x/(1-x^2),x)?

Stavros Macrakis macrakis at alum.mit.edu
Mon Feb 13 13:37:29 CST 2006


> Maxima currently says
>
> integrate(x/(1-x^2),x) ->
> -log(1-x^2)/2
>
> integrate(x/(x^2-1),x) ->
> log(x^2-1)/2

I must be missing something obvious here.  These both seem like correct answers.

Are you expecting them to both be giving results real for abs(x)<1 or
for abs(x)>1?




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